# prime number

Alyssa
prime number
Posted in : Java Beginners
this project is to determine if a phone number is a prime number. if the number is a prime number then print a message to the effect. if the number is not a prime number then print the prime factors of the number. allow the user to continue entering numbers for as long as he or she wishes.

i was given the following, but its not quite right and perhaps not quite complete:

for(count = 5; count <3; count = count +2)
{
x=0;
sq = Math.sqrt(count)
prime = true;
while(a[x]<sq,&&prime)
{
if(count % a(x) ==0)
prime = false;
else
x++;
}
if(prime)
a[index] = count;
index++;
}

May 10, 2010 at 12:57 PM

Hi Friend,

Try the following code:

import java.util.*;
class CheckPrime{
static boolean isPrime(long number){
boolean isPrime=false;
int i=(int) Math.ceil(Math.sqrt(number));
while (i>1){
if ((number!=i) && (number%i==0)){
isPrime=false;
break;
}
else if (!isPrime)
isPrime=true;
--i;
}
return isPrime;
}
public static void main(String[] args){
Scanner input=new Scanner(System.in);
boolean quit = false;
System.out.println("1. Check");
System.out.println("2. Exit");
do{
System.out.println();

case 1:
System.out.println("Enter number to check: ");
long num=input.nextLong();
if(isPrime(num)){
System.out.println("Hello");
}
else{
System.out.println("Factors are:");
for(int i=1;i<num;i++){
if(num % i == 0){
if(isPrime(i)){
System.out.println(i);
}
}
}
}
break;
case 2:
quit = true;
break;
}
}
while(!quit);
}
}

Thanks

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