Two- Dimensional Array 4 Answer(s) 3 years and 3 months ago
Posted in : Java Beginners
I am new in java programming. I am creating a two-dimensional array. This is my code ** class BinaryNumbers { public static void main(String[] args) { //create a two-dimensional array int ROWS = 21; int COLS = 2;
int[][] a2 = new int[ROWS][COLS];
//... Print array in rectangular form for (int i =0; i < ROWS; i++) { for (int j = 0; j < COLS; j++) { System.out.print(" " + a2[i][j]); } System.out.println(""); } } } I want to enter this data into this array Decimal Binary 1 1 2 10 3 11 4 100 5 101 6 110 7 111 8 1000 9 1001 10 1010 11 1011 12 1100 13 1101 14 1110 15 1111 16 10000 17 10001 18 10010 19 10011 20 10100 how can i do this? Please help me
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February 22, 2010 at 12:48 PM
Hi Friend,
Try the following code:
class BinaryNumbers { static int ROWS = 20; static int COLS = 2; public static void main(String[] args){ int a2[][]={{1,1},{2,10},{3,11},{4,100},{5,101},{6,110},{7,111},{8,1000},{9,1001},{10,1010},{11,1011}, {12,1100},{13,1101},{14,1110},{15,1111},{16,10000},{17,10001},{18,10010},{19,10011},{20,10100}}; System.out.println("Decimal Binary"); for (int i =0; i < ROWS; i++) { for (int j = 0; j < COLS; j++) { System.out.print(" " + a2[i][j]); } System.out.println(""); } } }
Thanks
February 23, 2010 at 12:00 AM
Hey, Here is the code which builds Binary Numbers dynamically where you need not give binary numbers explicitly. Just the decimal no. is sufficient.
public class BinaryNumbers {
public static void main(String[] args) { int ROWS = 26; int COLS = 2; int[][] binaryArray = new int[ROWS][COLS]; for (int i = 1; i < ROWS; i++) { String binaryNo = Integer.toBinaryString(i); for (int j = 0; j < COLS - 1; j++) { binaryArray[i][j] = i; binaryArray[i][++j] = Integer.parseInt(binaryNo); } } for (int i = 1; i < ROWS; i++) { for (int j = 0; j < COLS; j++) { System.out.print(binaryArray[i][j] + " "); } System.out.println(""); } }
}
February 23, 2010 at 12:17 AM
Hi, Here is another code same as above that prints binary numbers on the fly with little modification. Just give how many no.of binary numbers you wanna print starting from 1 in the console.May seem complex, but easy..
import java.util.Scanner;
public class BinaryNumbers {
public static void main(String[] args) { System.out .println("Enter the no. of binary numbers you want to print : "); Scanner scan = new Scanner(System.in); int ROWS = scan.nextInt() + 1; int[][] binary = new int[ROWS][]; for (int i = 1; i < ROWS; i++) { String binaryNo = Integer.toBinaryString(i); binary[i] = new int[2]; binary[i][0] = i; binary[i][1] = Integer.parseInt(binaryNo); } /* Print Array */ for (int i = 1; i < ROWS; i++) { System.out.println(binary[i][0] + " " + binary[i][1]); } } }
Snippet of o/p:
Enter the no. of binary numbers you want to print : 40 1 1 2 10 3 11 4 100 . . . 38 100110 39 100111 40 101000
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**
class BinaryNumbers
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public static void main(String[] args)
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