Hi Friend,

Try the following code:

1)import java.util.*;
import java.util.regex.*;
public class ShortestWord{
public static void main (String args[]){
System.out.print ("Enter a sentence: ");
Scanner input=new Scanner(System.in);
String str=input.nextLine();
String[] words = str.split(" ");
String word="aaaaaa";
for (int i=0;i<words.length;i++){
if (words[i].length() < word.length())
word = words[i];
}
System.out.println("Shortest word is: "+word);
int len = word.length();
int index = 0;
int start = str.indexOf(word);
while (start != -1){
index++;
start = str.indexOf(word, start+len);
}
System.out.println("Its position is: "+index);
}
}

Thanks

Hi Friend,

Try the following code:

import java.util.*;

public class Digits {

public static void main(String[] args) {
int oddCount=0;
int evenCount=0;
int zeros=0;
System.out.println("Enter multi digit number.");
Scanner input = new Scanner(System.in);
int number = 0;
int[] nums=new int[9];
while (input.hasNextInt(9)) {
number = input.nextInt();
String myString = Integer.toString(number) ;
nums = new int[myString.length()];
for(int i = 0; i < nums.length; i++){
nums[i] = myString.charAt(i) - '0';
}
//To find number of odds
for(int j=0;j<nums.length;j++)
if(nums[j] % 2 == 1) {
oddCount++;
}
System.out.println("Number of odds: "+oddCount);
//To find number of evens
for(int j=0;j<nums.length;j++)
if(nums[j] % 2 == 0) {
evenCount++;
}
System.out.println("Number of evens: "+evenCount);
//To reverse number
int reverse = Integer.parseInt( new StringBuffer( ""+number ).reverse().toString() );
System.out.println("Reverse Number = " + reverse );
}
}

}

Thanks

Hi Friend,

Use following code in your Digits.java class to count the number of zeros present in the input digit.

for(int j=0;j<nums.length;j++)
if(nums[j]<1) {
zeros++;
}
System.out.println("Number of Zeroes = " + zeros );

Thanks