OOP with Java-Array



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OOP with Java-Array
1 Answer(s)      8 years ago
Posted in : Java Beginners
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March 20, 2009 at 11:44 PM

Hi Friend,

Here is the code for solving your problem. Please try the following code:

import java.io.*;

public class AirlineReservation {

public static void main(String args[]) throws Exception {

String[][] seats = new String[7][4];

for (int i = 0; i < 7; i++) {
seats[i][0] = "A";
seats[i][1] = "B";
seats[i][2] = "C";
seats[i][3] = "D";

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

while (true) {
System.out.println("1. Display");
System.out.println("2. Assign");
System.out.println("3. Exit");
System.out.println("Enter your choice : ");

String choice = br.readLine();

switch (Integer.parseInt(choice)) {
case 1:

case 2:

case 3:

System.out.println("Invalid input");

public static void display(String seats[][]) {
for (int i = 0; i < 7; i++) {
System.out.print(i + 1);
for (int j = 0; j < 4; j++) {
System.out.print(" " + seats[i][j]);

public static void assign(String seats[][]) throws Exception {


BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter row = ");
String row = br.readLine();
System.out.println("Enter seat (A, B, C, D) = ");
String col = br.readLine();

for (int i = 0; i < 4; i++) {

if (seats[Integer.parseInt(row) - 1][i].equalsIgnoreCase(col)) {
seats[Integer.parseInt(row) - 1][i] = "X";

public static void exit() {

RoseIndia Team


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