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shakti rath
java call by reference
1 Answer(s)      6 years and a month ago
Posted in : Java Beginners



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November 19, 2008 at 12:49 AM


Hi friend,


When you call a method by reference, the callee sees the caller?s original variables passed as parameters, not copies. References to the callee?s objects are treated the same way. Thus any changes the callee makes to the caller?s variables affect the caller?s original variables. Java never uses call by reference. Java always uses call by value.


Here is the simple code.

import java.io.*;
import java.awt.*;

public class callByReference {
public static void main(String[] args) {
System.out.println("This is call by reference example");
Rectangle rec = new Rectangle(20,30,200,50);
System.out.println("Before move up massage");
System.out.println("After move up massage display");
moveUp(rec);
System.out.println("r1 is now\n" + rec);
}
static void moveUp(Rectangle rect) {
rect.translate(0,-20);
}
}

--------------------------
Visit for more information.

http://www.roseindia.net/java/


Thanks.


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