sunnychadha
i want a number in a specific range in pattern matcher..for example a number should only be in the range of 6-9 digits...if it exceeds or decrease it should show an error.Here is the code which i am trying...i this it checks for 10 digits...but i want it in the range of 6-9
import java.util.regex.Matcher; import java.util.regex.Pattern;
public class ValidatePhoneNumber { public static void main(String[] argv) {
String sPhoneNumber = tf.getText();
Pattern pattern = Pattern.compile("\\d{10}");
Matcher matcher = pattern.matcher(sPhoneNumber);
if (matcher.matches()) {
System.out.println("Phone Number Valid");
}
else
{
System.out.println("Phone Number not valid");
}
} }
November 23, 2012 at 10:57 PM
import java.io.*;
import java.util.regex.*;
class pmatch
{
public static void main(String args[])throws IOException
{
Pattern p=Pattern.compile("[0-9]{9}|[0-9]{8}|[0-9]{7}|[0-9]{6}");
System.out.println("Enter no.");
BufferedReader br=new BufferedReader (newInputStreamReader(System.in));
String exp=br.readLine();
Matcher m=p.matcher(exp);
boolean b=m.matches();
if(b==true)
System.out.println("Valid number");
else
System.out.println("Invalid number");
}
}
November 24, 2012 at 12:12 PM
Here is a code that validates phone number.
import java.util.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class ValidatePhoneNumber {
public static boolean validatePhone(String phone) {
return phone.matches("^[0-9]{6,9}$");
}
public static void main(String[] argv) {
Scanner input = new Scanner(System.in);
System.out.print("Enter Phone Number: ");
String phone = input.nextLine();
while (validatePhone(phone) != true) {
System.out.print("Invalid PhoneNumber!");
System.out.println();
System.out.print("Enter Phone Number: ");
phone = input.nextLine();
}
}
}
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