QuestionAsk Questions?
Jagannath
public class A {
int i;
int j;
void funA()
{
i = i+1;
System.out.println(i);
j = j+1;
System.out.println(j);
}
}
......................................................................
public class Demo<G> {
G x;
public static void main(String[] args) {
Demo<A> d3 = new Demo<A>();
try
{
d3.x.i = 5;//why Null pointer Exception
}
catch (Exception e) {
e.printStackTrace();
}
}
}
View Answers
December 31, 2012 at 3:20 PM
Hi jagan,
Before you have assign the value for i, you should declare x object explicitly with new operator d3.x = new A(); d3.x.i = 5; Now null pointer exception won't come.
public class Demo<G> {
G x;
public static void main(String[] args) {
Demo<A> d3 = new Demo<A>();
try
{
d3.x = new A();
d3.x.i = 5;//why Null pointer Exception
}
catch (Exception e) {
e.printStackTrace();
}
}
}
Please try with this code.
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