Program to list all even numbers between two numbers in JAVA

import java.io.*;
import java.lang.*;
class Evennumbers{
public static void main(String[] args){
try{
DataInputStream d=new DataInputStream(System.in);
System.out.println("Enter the number:");
int n=Integer.parseInt(d.readLine());
System.out.println("Even numbers");
for(int i=1;i<=n;i++){
if(i%2=0){
System.out.println(i+",");
}
}
}
catch(Exception e){ }

}
}

See how the above given program code "even numbers between two numbers " works...


For getting the even numbers between numbers given by the user.

1. first of all we have to include the following packages such as ;

import java.io.*;// include this package

import java lang.*;.//this is default package you may include it or not

2.After that specify name of class such as

class Evennumbers // name of the class

3. public static void main(String arr[]) // from here program starts the execution

4. DataInputStream d=new DataInputStream(System.in); //for getting the input from keyboard by user use this

System.in // converts the byte stream into the character stream

5.System.out.println("Enter the number:") // for displaying message

6. int n=Integer.parseInt(d.readLine()) // d.readLine() for reading the input given by the keyboard

// Integer.parseInt() for converting the character data into the integer format

7.System.out.println("Even numbers") // again diplaying message

8.for(int i=1;i<=n;i++) // for given more than one numbers

9. if(i%2=0) // used this for checking the condition , of number given by the user

//we used here == double equal to because = is used only for asign the value to the variable not for checking the condition

10. System.out.println(i+",") // for diplaying the output

11. try{}catch{} // block for exception handling that will be thrown by the program

12. // for getting the output in single line use this System.out.print(i+",") in place of System.out.println(i+",")

// output will be like this 2,4,6,8


Good luck ;)