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Manoj Hunasigi
collections
1 Answer(s)      6 years ago
Posted in : Java Beginners

please explain me d flow


import java.util.*;

public class Array{
    public static void main(String[] args){
        int arr[]={10,45,25,6,78,12,21};
        int arr1[]={10,45,25,6,78,12,21};
        int arr2[]={10,45,85,45,12,78,296};

        for (int i=0;i<arr.length;i++){
            System.out.println(arr[i]+"\t");}
        for(int i=0;i<arr1.length;i++){
            System.out.println(arr1[i]+"\t");}
        for(int i=0;i<arr2.length;i++){
            System.out.println(arr2[i]+"\t");


        }
        System.out.println("\n ******arr After sorting*****");
        Arrays.sort(arr);
        for (int i=0;i<arr.length;i++){
            System.out.println(arr[i]+"\t");


        }

        System.out.println();
        System.out.println(Arrays.binarySearch(arr,6));
        System.out.println(Arrays.binarySearch(arr,9));
        System.out.println(Arrays.equals(arr,arr1));
        System.out.println(Arrays.equals(arr,arr2));

        Arrays.fill(arr,32);
        for (int i=0;i<arr.length;i++){
            System.out.println(arr[i]+"\t");
        }
        Object ob[]={"jlc","india","sri","vas","white","red"};
        for (int i=0;i<ob.length;i++){
            System.out.println(ob[i]+"\t");
        }
        System.out.println();
        List list= Arrays.asList(ob);
        Iterator it=list.iterator();
        while(it.hasNext()){
            System.out.println(it.next()+"\t");
        }
        System.out.println();
        Arrays.sort(ob);
        for (int i=0;i<ob.length;i++){
            System.out.println(ob[i]+"\t");
        }
        System.out.println();
    }}

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April 20, 2011 at 11:46 AM


In the given code, 3 arrays of integer type have been defined. Then using the for loop, the array elements have been displayed. Then the method Arrays.sort(arr) sort the values of first array and display the array in the sorted order. The method binarySearch(arr, 6) searches the element 6 in the first array and returns 0 as after sorting the array, the position of the element 6 is changed to 0. As there is no element 9 in the array, so it returns negative value. The method equals compare the two arrays and found that neither arr equals to arr1 nor arr equals to arr2. As the position of element changed in arr after sorting the array. The method Arrays.fill(arr,32) assign the value 32 to each element of the array 'arr'.

Then there is another array of object type has been defined. Then using the Arrats.asList() method, this array has been converted into List which is then iterated using Iterator class and display the values of List. After that, using the method Arrays.sort(), the elements of Object arrat get sorted and displayed.










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