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ramachandra
Interface
1 Answer(s)      3 years and 10 months ago
Posted in : Java Beginners


1.Create an interface names ShapeInterface that has two methods and one constant and an abstract class named ShapeAbstract that has two instance variable, one abstract and one non-abstract method. Create a concrete class a.Rectangle that uses the interface b.Circle that uses the interface and abstract class


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March 8, 2011 at 12:35 PM


interface ShapeInterface{
    int l=0,b=0;
    public void area();
    public void perimeter();
}
abstract class ShapeAbstract  {
    double PI=3.14,r=0;
    public void areaOfCircle() {
    }
abstract public void circumference();
}
 class Rectangle implements ShapeInterface{
int l=10,b=5;
public void area(){
    int ar=l*b;
    System.out.println("Area of Rectangle: "+ar);
}

public void perimeter(){
    int k=l+b;
    int p=2*k;
    System.out.println("Perimeter of Rectangle: "+p);
}
}
 class Circle extends ShapeAbstract implements ShapeInterface {
    int r=5;
    int l=15,b=10;
    public void areaOfCircle() {
    double area=PI*r*r;
    System.out.println("Area of Circle: "+area);
    }
    public void circumference(){
    double cir=2*PI*r;
    System.out.println("Circumference of Circle: "+cir);
    }

    public void area(){
    int ar=l*b;
    System.out.println("Area of Rectangle: "+ar);
}
public void perimeter(){
    int k=l+b;
    int p=2*k;
    System.out.println("Perimeter of Rectangle: "+p);
}
}
class InterfaceAndAbstractClass{
    public static void main(String[]args){
    Rectangle a=new Rectangle();
    a.area();
    a.perimeter();
    System.out.println();
    Circle b=new Circle();
    b.areaOfCircle();
    b.circumference();
    b.area();
    b.perimeter();
    }
}


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