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moni sharma
array and string based problem
1 Answer(s)      3 years and 6 months ago
Posted in : Java Beginners


this program is accepting only integers as input but i want to modify it such that it can accept both integers and char. import java.util.*; public class Insertion1 { public static void insertion_srt(int array[],int n){ for (int j = 0; j < n; j++){ int i = j-1; int k = array[j]; while ((i>= 0) && (array[i] > k)){ array[i+1]=array[i]; i=i-1; array[i+1]=k; } } } public static void main(String a[]){ Scanner input=new Scanner(System.in); int array[]=new int[10]; int i;

System.out.println(" Selection Sort\n\n");
System.out.println("Values Before the sort:\n");
for(i = 0; i < array.length; i++){ array[i]=input.nextInt(); } for(i = 0; i < array.length; i++){ System.out.println(array[i]); }

insertion_srt(array, array.length);
System.out.print("Values after the sort:\n");
for(i = 0; i

System.out.println("PAUSE"); } }


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January 5, 2011 at 1:10 PM


Hi Friend,

Try the following code:

import java.util.*;
public class StringArraySelectionSort {

    public static void main(String[] args)throws Exception{
    Scanner input=new Scanner(System.in);
    System.out.println("Enter number or char");
    char[] array = new char[5];
    for(int i=0;i<5;i++){
        char ch=input.next().charAt(0);
        array[i]=ch;
    }
    selectionSort(array);
    for(int i = 0; i < array.length; i++){
    System.out.print(array[i]+" ");
     }
    }
    static char[] selectionSort(char[] array)
    {
        for (int i = 1; i < array.length; i++) {
            int s = i-1;
            for (int j = i; j < array.length; j++) {
                if (Character.toString(array[j]).compareTo(Character.toString(array[s])) < 0) {
                    s = j;
                }
            }
            char temp = array[i-1];
            array[i-1] = array[s];
            array[s] = temp;

        }
        return array;
    }
}

Thanks



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