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Dnyanesh Khedekar
Prime Numbers from range
2 Answer(s)      3 years and 8 months ago
Posted in : Java Beginners


how to find prime numbers in a given range which are palindromes??


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December 21, 2010 at 5:12 PM


Hi Friend,

Try the following code:

import java.util.*;

public class PrimeAndPalindrome {
   static final int MAXNUMBER=200;
   private int number;
   private ArrayList<Integer> list = new ArrayList<Integer>();
   public PrimeAndPalindrome(int maxNum){
   number=maxNum;
   }
 ArrayList<Integer> isPalindrome(){
      for (int i=10; i<=number; i++){
         Integer in=new Integer(i);
         String number=in.toString();
         int index1=0;
         int index2=number.length()-1;
         char x=number.charAt(index1);
         char y=number.charAt(index2);
         while (index2-index1>=0){
         if(x!=y)
         break;
         if (index2-index1==0 || index2-index1==1)
         list.add(i);
         index1++;
         index2--;
         x=number.charAt(index1);
         y=number.charAt(index2);
         }
      }
      return list;
   }
   static boolean isPrime(int number){
      boolean isPrime=false;
      int i=(int) Math.ceil(Math.sqrt(number));
      while (i>1){
         if ((number!=i) && (number%i==0)){
            isPrime=false;
            break;
         }
         else if (!isPrime)
         isPrime=true;
         --i;
      }
      return isPrime;
   }
   public static void main(String[] args) {
      ArrayList<Integer> palindromes=new ArrayList<Integer>();
      PrimeAndPalindrome pp=new PrimeAndPalindrome(MAXNUMBER);
      palindromes=pp.isPalindrome();
      Iterator<Integer> iter=palindromes.iterator();
      while (iter.hasNext()){
         int current=iter.next();
         if (isPrime(current))
            System.out.println(current);
      }
   }
}

Thanks



December 23, 2010 at 10:49 AM


thnks buddy..but can u clearify what that ArrayList exactly doing?



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