QuestionAsk Questions?
siti umairah
what is the differences between printf and println?
View Answers
December 8, 2010 at 4:45 PM
Hi Friend,
The println prints the text on a new line, where as printf prints the text on the same line.
Thanks
Related Pages:
printf and println
printf and println what is the differences between printf and println? Hi Friend, The println prints the text on a new line, where as printf prints the text on the same line. Thanks
printf and println what is the differences between printf and println? Hi Friend, The println prints the text on a new line, where as printf prints the text on the same line. Thanks
For printing out strings, there are echo, print and printf. Explain the differences.
For printing out strings, there are echo, print and printf. Explain the differences. For printing out strings, there are echo, print and printf. Explain the differences
For printing out strings, there are echo, print and printf. Explain the differences. For printing out strings, there are echo, print and printf. Explain the differences
Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times)
Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times) Can u print... ++a in the same printf() command ten times
Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times) Can u print... ++a in the same printf() command ten times
Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times)
Can u print in turbo C Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times
Can u print in turbo C Can u print in turbo c 9 8 7 6 5 4 3 2 1 0 using pre increment operator Only use print ++a in the same printf() command ten times
Formatted Output
Java NotesFormatted Output Java 5 implements formatted output with printf(). This concept will be very familiar to C and Fortran programmers. A good...() method (and in some cases also the equivalent printf() method from C
Java NotesFormatted Output Java 5 implements formatted output with printf(). This concept will be very familiar to C and Fortran programmers. A good...() method (and in some cases also the equivalent printf() method from C
3
java.io package The java.io package includes a PrintStream class that has two formatting methods that we can use to replace print () and println...;The methods are printf() and format().These methods writes a formatted string
java.io package The java.io package includes a PrintStream class that has two formatting methods that we can use to replace print () and println...;The methods are printf() and format().These methods writes a formatted string
>, <
>, < main() { float a=0.7; if(a<0.7) printf("lesser"); else printf("greater"); } Output: lesser main() { float a=1.2; if(a<1.2) printf("lesser"); else printf("greater"); } Output: greater HOW
>, < main() { float a=0.7; if(a<0.7) printf("lesser"); else printf("greater"); } Output: lesser main() { float a=1.2; if(a<1.2) printf("lesser"); else printf("greater"); } Output: greater HOW
Java IO PrintWriter
) printf(Locale l, String format, Object... args) : This method... and arguments, to the writer. Syntax : public PrintWriter printf(Locale l, String format, Object... args) printf(String format, Object... args) : This method
) printf(Locale l, String format, Object... args) : This method... and arguments, to the writer. Syntax : public PrintWriter printf(Locale l, String format, Object... args) printf(String format, Object... args) : This method
Tricky
Tricky if() printf("Hello") else printf("world") what should be he condition such that o/p is both hello and world as helloworld
Tricky if() printf("Hello") else printf("world") what should be he condition such that o/p is both hello and world as helloworld
Convert To Java Program - Java Beginners
check(); void main() { int num; printf("\nMenu\n"); printf("1-Add\n"); printf("2-Delete\n"); printf("3-Insert\n"); printf("4-Display\n"); printf... add() { printf("Enter value: "); scanf("%d",&array[cntr]); cntr
check(); void main() { int num; printf("\nMenu\n"); printf("1-Add\n"); printf("2-Delete\n"); printf("3-Insert\n"); printf("4-Display\n"); printf... add() { printf("Enter value: "); scanf("%d",&array[cntr]); cntr
C program - SQL
void main() { int i,j; int * pt; clrscr(); printf(" "); printf("\n...=&k; printf("%4d", *pt); } printf("\n"); } getch(); } Thanks
void main() { int i,j; int * pt; clrscr(); printf(" "); printf("\n...=&k; printf("%4d", *pt); } printf("\n"); } getch(); } Thanks
jan
jan write code to input a word and printf the next consecutive letter of each alphabet input :EARTH output :FBSUI
jan write code to input a word and printf the next consecutive letter of each alphabet input :EARTH output :FBSUI
c programe
++){ printf("%d",j); } for(int j = 0; j < 5-i; j++){ printf(" "); } for(int j=i;j>=1;j--){ printf("%d",j); } printf("\n"); getch(0
++){ printf("%d",j); } for(int j = 0; j < 5-i; j++){ printf(" "); } for(int j=i;j>=1;j--){ printf("%d",j); } printf("\n"); getch(0
program of c
program of c write a program in c to display a to z without using printf or scanf statements or header files
program of c write a program in c to display a to z without using printf or scanf statements or header files
ANZ PLZ
ANZ PLZ FIND DISCRIPTION ABOUT print () and println ()METHODS ... the output: hellohi The println() method prints on a new line. It makes the cursor to be placed in the next line of the displayed command. For example: println
ANZ PLZ FIND DISCRIPTION ABOUT print () and println ()METHODS ... the output: hellohi The println() method prints on a new line. It makes the cursor to be placed in the next line of the displayed command. For example: println
java
java what 2 access modifiers that can encapsulate the attributes of class?? and what is the concept of printf? Hello Friend, Public and Private can encapsulate the attributes of class. Printf formats the strings
java what 2 access modifiers that can encapsulate the attributes of class?? and what is the concept of printf? Hello Friend, Public and Private can encapsulate the attributes of class. Printf formats the strings
implementation of stacks using linked lists in c++
choice,data; clrscr(); while(1){ printf("\n1.Push\n2.Pop\n3.Display\n4.Exit\n"); printf("\nEnter ur choice:"); scanf("%d",&... *)malloc(sizeof(struct node)); printf("Enter a node data :"); scanf
choice,data; clrscr(); while(1){ printf("\n1.Push\n2.Pop\n3.Display\n4.Exit\n"); printf("\nEnter ur choice:"); scanf("%d",&... *)malloc(sizeof(struct node)); printf("Enter a node data :"); scanf
C Program to Print Pascal Triangle - Development process
void main(){ int a[15][15],i,j,rows,num=25,k; printf("\n enter the number of rows:"); scanf("%d",&rows); for(i=0;i=0;k--) printf(" "); for(j=0;j<...]; } printf("%4d",a[i][j]); } printf("\n"); } getch(); } Thanks
void main(){ int a[15][15],i,j,rows,num=25,k; printf("\n enter the number of rows:"); scanf("%d",&rows); for(i=0;i=0;k--) printf(" "); for(j=0;j<...]; } printf("%4d",a[i][j]); } printf("\n"); } getch(); } Thanks
Managment
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
Managment
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
Managment
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
Managment
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
Managment
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
); gotoxy(27,2); printf("SUFYAN COMPANY Pvt.(Ltd.)"); gotoxy(35,3); printf("MAIN MENU"); lin(1,80,4,205); gotoxy(28,7); printf("1. ADDITION OF RECORD"); gotoxy(28,8
C Program to Print Stras - Development process
; int j=0; for(i=1;i<=4;i+=1){ printf("\n"); for(j=1;j<=i;j++) printf("*"); } printf("\n"); for(i=3;i>=0;i-=1){ for(j=0;j
; int j=0; for(i=1;i<=4;i+=1){ printf("\n"); for(j=1;j<=i;j++) printf("*"); } printf("\n"); for(i=3;i>=0;i-=1){ for(j=0;j
goto statement problem. reply fast.
; clrscr(); rep : printf("\nEnter the value rs"); scanf("%f",&rs); p=rs*100; printf("\n\npaisa =%2.f ",p); printf("\n do you want...; char z='y'; clrscr(); while(z=='y') { printf("\nEnter
; clrscr(); rep : printf("\nEnter the value rs"); scanf("%f",&rs); p=rs*100; printf("\n\npaisa =%2.f ",p); printf("\n do you want...; char z='y'; clrscr(); while(z=='y') { printf("\nEnter
Sum of array element in C
(); printf("Enter five elements for an array \n"); read(a,5); printf("The list elements are \n"); display(a,5); for(i=0;i<5;i++) { sum+=a[i]; } printf("The sum of the elements
(); printf("Enter five elements for an array \n"); read(a,5); printf("The list elements are \n"); display(a,5); for(i=0;i<5;i++) { sum+=a[i]; } printf("The sum of the elements
C Program for Addtion of 2*2 Diagnol Matrix - Development process
],b[2][2],c[2][2],i,j; clrscr(); printf("Enter the First matrix:\n"); for(i=0;i<2;i++) { for(j=0;j<2;j++){ scanf("%d",&a[i][j]); } } printf("\nThe First matrix is:\n"); for(i=0;i<2;i++) { printf("\n"); for(j=0;j<2;j
],b[2][2],c[2][2],i,j; clrscr(); printf("Enter the First matrix:\n"); for(i=0;i<2;i++) { for(j=0;j<2;j++){ scanf("%d",&a[i][j]); } } printf("\nThe First matrix is:\n"); for(i=0;i<2;i++) { printf("\n"); for(j=0;j<2;j
C program - Java Magazine
: #include #include void main(){ int a,b,c,area,ar; clrscr(); printf("Enter first integer:\n"); scanf("%d", &a); printf("Enter second integer:\n"); scanf("%d", &b); printf("Enter third integer:\n"); scanf("%d
: #include #include void main(){ int a,b,c,area,ar; clrscr(); printf("Enter first integer:\n"); scanf("%d", &a); printf("Enter second integer:\n"); scanf("%d", &b); printf("Enter third integer:\n"); scanf("%d
Push and Pop operation of stack.
) { *top = *top + 1; stack[*top] = value; printf("\nStack element should be less than four\n"); } else { printf("\nThe stack is full... - 1; } else { printf("\nThe stack is empty can not pop a value
) { *top = *top + 1; stack[*top] = value; printf("\nStack element should be less than four\n"); } else { printf("\nThe stack is full... - 1; } else { printf("\nThe stack is empty can not pop a value
c file compilation
) feature[i]==1) printf("-1 "); else printf("+1 "); */ // printf("%f ", feature[1]); printf("%d ", (int) feature[0]); for(j=1;j<i;j++) printf(" %d:%f",j,feature[j]); printf("\n
) feature[i]==1) printf("-1 "); else printf("+1 "); */ // printf("%f ", feature[1]); printf("%d ", (int) feature[0]); for(j=1;j<i;j++) printf(" %d:%f",j,feature[j]); printf("\n
C Program - Development process
d; int nr; int dr; clrscr(); printf("Enter the first fraction in the form a/b: "); scanf("%d/%d", &a, &b); printf("Enter the second fraction in the form a/b: "); scanf("%d/%d", &c, &d); nr=a*d; dr=b*c; printf("%d/%d",nr,dr
d; int nr; int dr; clrscr(); printf("Enter the first fraction in the form a/b: "); scanf("%d/%d", &a, &b); printf("Enter the second fraction in the form a/b: "); scanf("%d/%d", &c, &d); nr=a*d; dr=b*c; printf("%d/%d",nr,dr
Pointer and Structure in C
() { p=&r; clrscr(); printf("\nEnter the name\n"); scanf("\n%s",&p->name); printf("\nEnter the roll no\n"); scanf("%d",&p->roll); printf("\n%s",p->name); printf
() { p=&r; clrscr(); printf("\nEnter the name\n"); scanf("\n%s",&p->name); printf("\nEnter the roll no\n"); scanf("%d",&p->roll); printf("\n%s",p->name); printf
Array Implementation in C
size[5],i,sum=0; clrscr(); printf("Enter five elements for an array \n"); read(size,5); printf("All elements of the array...); } void display(int d[],int i) { int j; for(j=0;j<i;j++) printf("%d
size[5],i,sum=0; clrscr(); printf("Enter five elements for an array \n"); read(size,5); printf("All elements of the array...); } void display(int d[],int i) { int j; for(j=0;j<i;j++) printf("%d
Merge of two arrays in C
mergelist(int *,int *,int *,int); int a[5],b[5],c[10]; clrscr(); printf("Enter the elements for the first array \n"); read(a,5); printf("The elements of first array are : \n"); display(a,5); printf("
mergelist(int *,int *,int *,int); int a[5],b[5],c[10]; clrscr(); printf("Enter the elements for the first array \n"); read(a,5); printf("The elements of first array are : \n"); display(a,5); printf("
C Program - Development process
=0; for(j=0;j<3;j++){ for(k=0;k<3;k++) printf(" %3d",d[j][k]); printf("\n"); } for(j=0;j<3;j++) { sum1=sum1+d[j][j]; } k=3-1; for(j=0;j<3;j++) { if(k>=0){ sum2=sum2+d[j][k]; k--; } } printf
=0; for(j=0;j<3;j++){ for(k=0;k<3;k++) printf(" %3d",d[j][k]); printf("\n"); } for(j=0;j<3;j++) { sum1=sum1+d[j][j]; } k=3-1; for(j=0;j<3;j++) { if(k>=0){ sum2=sum2+d[j][k]; k--; } } printf
C,C++
C,C++ int i=100,j=20; int c=i&j; int r=i|j; printf("%d",c); printf("%d",r); #include<stdio.h> #include<conio.h> void main(){ int i=100,j=20; int c=i&j; int r=i|j; printf("%d",c); printf("%d",r
C,C++ int i=100,j=20; int c=i&j; int r=i|j; printf("%d",c); printf("%d",r); #include<stdio.h> #include<conio.h> void main(){ int i=100,j=20; int c=i&j; int r=i|j; printf("%d",c); printf("%d",r
c programming..what wil be the output of this program
c programming..what wil be the output of this program #include int main() { int arr[] = {0,1,2,3,4}; int i,*ptr; for (ptr=arr+4; ptr= arr; ptr--) { printf("%d",*ptr
c programming..what wil be the output of this program #include int main() { int arr[] = {0,1,2,3,4}; int i,*ptr; for (ptr=arr+4; ptr= arr; ptr--) { printf("%d",*ptr
Representing Graph using adjacency list & perform DFS & BFS
->top==max-1) printf("\n Queue Overflow"); else { s->...) { int x; if(empty(s)) printf("\n Queue Overflow..!"); else...;rear==max-1) printf("\n Queue Overflow..1"); else { q->
->top==max-1) printf("\n Queue Overflow"); else { s->...) { int x; if(empty(s)) printf("\n Queue Overflow..!"); else...;rear==max-1) printf("\n Queue Overflow..1"); else { q->
Posing
; @implementation FirstClass -(void)fShow { printf("... { printf("This is first class."); } @end... if ( [fClassObj isKindOfClass: [FirstClass class]] == YES ) { printf( "
; @implementation FirstClass -(void)fShow { printf("... { printf("This is first class."); } @end... if ( [fClassObj isKindOfClass: [FirstClass class]] == YES ) { printf( "
Dynamic Types in Objective-C
; @implementation FirstClass -(void)fShow { printf("... { printf("This is first class."); } @end... if ( [fClassObj isKindOfClass: [FirstClass class]] == YES ) { printf( "
; @implementation FirstClass -(void)fShow { printf("... { printf("This is first class."); } @end... if ( [fClassObj isKindOfClass: [FirstClass class]] == YES ) { printf( "
Sample code for An ASCII Encryption and Decryption code in C-language only.
is translated to 84w104w101space99w97w116 (hint: try printf("%d",'t');) Create...(); printf("Press 1 to Encrypt"); printf("Press 2 to Decrypt"); printf("Enter...: printf("Enter the filename to Encrypt:"); scanf("%s",fname); fp1
is translated to 84w104w101space99w97w116 (hint: try printf("%d",'t');) Create...(); printf("Press 1 to Encrypt"); printf("Press 2 to Decrypt"); printf("Enter...: printf("Enter the filename to Encrypt:"); scanf("%s",fname); fp1
Push and Pop operation of stack using linked list.
(sizeof(struct node)); if(temp==NULL) { printf("No Memory available...) { struct node *temp; if(p==NULL) { printf(" The stack is empty and cannot... *top = NULL; int n,value; do { do { printf("Enter the element
(sizeof(struct node)); if(temp==NULL) { printf("No Memory available...) { struct node *temp; if(p==NULL) { printf(" The stack is empty and cannot... *top = NULL; int n,value; do { do { printf("Enter the element
Queue implementation using array.
] = value; } else { printf("The queue is full \n"); exit(1...) { if(*front == rear) { printf("The queue is empty \n"); exit(1... { do { printf("Enter the element to be inserted
] = value; } else { printf("The queue is full \n"); exit(1...) { if(*front == rear) { printf("The queue is empty \n"); exit(1... { do { printf("Enter the element to be inserted
Queue implementation using linked list.
(struct node)); if(temp==NULL) { printf("No Memory available\n"... == NULL)) { printf(" The queue is empty can not delete Error\n"... { printf("Enter the element to be inserted\n"); scanf("
(struct node)); if(temp==NULL) { printf("No Memory available\n"... == NULL)) { printf(" The queue is empty can not delete Error\n"... { printf("Enter the element to be inserted\n"); scanf("
Circular queue implementation using array.
) % MAX; if(*rear == front) { printf("The queue is full\n"..., int rear, int * value) { if(*front == rear) { printf("The queue...; do { do { printf("Enter
) % MAX; if(*rear == front) { printf("The queue is full\n"..., int rear, int * value) { if(*front == rear) { printf("The queue...; do { do { printf("Enter
ONLINE EXAM CODE SPLIT
ques="#include<stdio.h>main(){int i;for(i=0;<100;i++){printf("hai...(){ int i; for(i=0;<100;i++){ printf("hai"); } } how is it possible? plz plz help
ques="#include<stdio.h>main(){int i;for(i=0;<100;i++){printf("hai...(){ int i; for(i=0;<100;i++){ printf("hai"); } } how is it possible? plz plz help
Write a C language program to read two matrices and multiply them?
= 0; int first[10][10], second[10][10], multiply[10][10]; printf("Enter...); printf("Enter the elements of first matrix\n"); for ( c = 0 ; c < m...]); printf("Enter the number of rows and columns of second matrix\n"); scanf("%d
= 0; int first[10][10], second[10][10], multiply[10][10]; printf("Enter...); printf("Enter the elements of first matrix\n"); for ( c = 0 ; c < m...]); printf("Enter the number of rows and columns of second matrix\n"); scanf("%d
If you are facing any programming issue, such as compilation errors or not able to find the code you are looking for.
Ask your questions, our development team will try to give answers to your questions.
Services
Home Privacy Policy
© All Rights are Reserved for Rose India
- Website Development
- Web Designing
- Web Redesigning
- Web Development
- Logo Design
- Web Design Packages
- Domain Registration
- Web Promotion Services
- SEO Services
- Search Eng. Optimization
- Search Eng. Submission
- SEO Tips
- SEO Portfolio
- Web Promotion Plans
Home Privacy Policy
© All Rights are Reserved for Rose India