# java leap year

Khema Edirisinghe
java leap year
1 Answer(s)      6 years and 10 months ago
Posted in : Java Beginners

write a java program that takes an input as a keyboard inputs or command line argument, a year between 1800 and 2000 and then reports whether itis a leap year. Aleap year is an integer greater than 1584 that is either divisible by 400 or is divisible by 4 but not 100

October 23, 2010 at 11:50 AM

Hi Friend,

Try the following code:

```import java.util.*;

public class LeapYear{
public static boolean isLeapYear(int year) {

if (year < 0) {
return false;
}
if (year % 4 == 0) {
return true;
}  else if (year % 400 == 0) {
return true;
}
else if (year % 100 == 0) {
return false;
}
else {
return false;
}
}
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.println("Enter any year:" );
int y = in.nextInt();
LeapYear year = new LeapYear();
if (year.isLeapYear(y)){
System.out.println("It is a leap year.");
}
else{
System.out.println("It is not a leap year.");
}
}
}
```

Thanks

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