java number to word 1 Answer(s) 2 years and 11 months ago
Posted in : Java Beginners
Can somebody please fix this to come out with the word, not the number 23?
import java.util.Scanner;
public class WordExtractor5 { //----------------------------------------------------------------- // Pulls integers from a string to form a word. //----------------------------------------------------------------- public static void main (String[] args) { Scanner scan=new Scanner(System.in); String strLineOfText; String word = ""; int character;
System.out.print("Enter a line of text: " );//The cat in the hat 18 characters strLineOfText = scan.nextLine();
System.out.println(); // blank line
System.out.print("Enter an integer for the starting character " + "position followed by 5 integers \nspecifying the number of " + "characters to move from the previous character \nto the next " + "to extract a 6-character word: " ); character = scan.nextInt()-1; character += scan.nextInt(); character += scan.nextInt(); character += scan.nextInt(); character += scan.nextInt(); character += scan.nextInt();
System.out.println ();
System.out.print("The word you extracted is:= " + character );
} }
View Answers
June 30, 2010 at 3:15 PM
Hi Friend,
Try the following code:
import java.util.Scanner;
public class WordExtractor5{ public static void main (String[] args){ Scanner scan=new Scanner(System.in); String strLineOfText; String word = ""; int character;
System.out.print("Enter a line of text: " ); strLineOfText = scan.nextLine();
System.out.println();
System.out.print("Enter an integer for the starting character " + "position followed by 5 integers \nspecifying the number of " + "characters to move from the previous character \nto the next " + "to extract a 6-character word: " ); character=scan.nextInt(); word=strLineOfText.substring(character,character+6); System.out.println (); System.out.print("The word you extracted is:= " + word ); } }
Thanks
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