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vikas pandey
illegal start of expression in servlet error..
0 Answer(s)      2 years and 2 months ago
Posted in : JSP-Servlet


hello Sir, here is my servlet code and i am getting illegal start of expression error in declaring the method named " public Boolean ModificarUsuario(int IdUsuario, String Usuario, String Email) {"

plz help me out to solve the problem .thank you Sir.

public class edit extends HttpServlet {

protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/html;charset=UTF-8");
    PrintWriter out = response.getWriter();



public Boolean ModificarUsuario(int IdUsuario, String Usuario, String Email) {
    try {

        conexion conexiondb = new conexion();
        conexiondb.Conectar();

        String strQuery = "";
        strQuery = "UPDATE gridjq SET nombre_Usuario='" + Usuario + "', email_Usuario='" + Email + "' WHERE id_Usuarios = '" + IdUsuario + "'";

        if (!conexiondb.Ejecutar(strQuery)) {
            conexiondb.Close();
            return false;

        }
        conexiondb.Close();

    } catch (Exception e) {
        String msg = e.getMessage();
    }
    return true;
}

}


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