execution of java program

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Ajay Bhushan.B
execution of java program
1 Answer(s)      5 years and 10 months ago
Posted in : JDBC

wat are the steps for the execution of the servlet-jdbc program on tomcat 5.5 server.. PlS provide..the execution steps in detail..including the setting of classpath in DOS for mysql-connector-java.

i have put the classpath as:

set path=%path%;C:\Program Files\Java\jdk1.6.0_01\bin

javac LoginServlet.java -classpath "C:\Program Files\Apache Software Foundation\Tomcat 5.5\common\lib\servlet-api.jar";"C:\Program Files\Apache Software Foundation\Tomcat 5.5\common\lib\mysql-connector-java-3.0.17-ga-bin.jar"; is this correct way ?THANKYOU!!!

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October 31, 2011 at 12:01 PM


Put servlet-api.jar and mysql-connector.jar files in the Tomcat5.5/lib/ folder.

Please visit the following links:

http://www.roseindia.net/servlets/HowToRunAServlet.shtml

http://www.roseindia.net/servlets/databaseconnectionservlet.shtml

Servlet Tutorials


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