C sum of two matrices

The given code allow the user to enter the number of rows and columns of matrix. Accordingly, the code accepts the row and column values from the user and determine their sum.

#include <stdio.h>
#include <conio.h>

void main()
{
   int m, n, c, d, first[10][10], second[10][10], sum[10][10];

   printf("Enter the number of rows and columns of matrix ");
   scanf("%d%d", &m, &n);
   printf("Enter the elements of first matrix\n");

   for ( c = 0 ; c < m ; c++ )
      for ( d = 0 ; d < n ; d++ )
         scanf("%d", &first[c][d]);

   printf("Enter the elements of second matrix\n");

   for ( c = 0 ; c < m ; c++ )
      for ( d = 0 ; d < n ; d++ )
            scanf("%d", &second[c][d]);

   for ( c = 0 ; c < m ; c++ )
      for ( d = 0 ; d < n ; d++ )
         sum[c][d] = first[c][d] + second[c][d];

   printf("Sum of entered matrices:-\n");

   for ( c = 0 ; c < m ; c++ )
   {
      for ( d = 0 ; d < n ; d++ )
         printf("%d\t", sum[c][d]);

      printf("\n");
   }
   getch();

}

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C Sum of two matrices

C++ Sum of matrix

The given code allow the user to enter the number of rows and columns of matrix. Accordingly, the code accepts the row and column values from the user and determine their sum.

#include<iostream>
 #include<stdio.h>
 #include<conio.h>

    using namespace std;

   void main()
    {
       int m, n, c, d, first[10][10], second[10][10], sum[10][10];

       cout << "Enter the number of rows and columns of matrix ";
       cin >> m >> n;
       cout << "Enter the elements of first matrix\n";

       for (  c = 0 ; c < m ; c++ )
          for ( d = 0 ; d < n ; d++ )
             cin >> first[c][d];

       cout << "Enter the elements of second matrix\n";

       for ( c = 0 ; c < m ;c++ )
          for ( d = 0 ; d < n ; d++ )
                cin >> second[c][d];

       for ( c = 0 ; c < m ; c++ )
          for ( d = 0 ; d < n ; d++ )
             sum[c][d] = first[c][d] + second[c][d];

       cout << "Sum of entered matrices:-\n";

       for ( c = 0 ; c < m ; c++ )
       {
          for ( d = 0 ; d < n ; d++ )
             cout << sum[c][d] << "\t";

          cout << endl;
       }

      getch();
    }