in html how can we can upload the file
<tr> <td><strong>Video of the work:</strong> <td><b> <input type="text" name="Video of the work:" size="30"> </b> </td> </tr>
after this i want the upload button with form action when i click the upload button it wil goto some where to upload the file give me the code for this in html and java
1)page.html: <%@ page language="java" %> <HTML> <HEAD><TITLE>Display file upload form to the user</TITLE></HEAD> <BODY> <FORM ENCTYPE="multipart/form-data" ACTION="http://localhost:8080/examples/UploadServlet" METHOD=POST> <br><br><br> <center> <table border="0" bgcolor=#ccFDDEE> <tr> <center> <td colspan="2" align="center"><B>UPLOAD THE FILE</B><center></td> </tr> <tr> <td colspan="2" align="center"> </td> </tr> <tr> <td><b>Choose the file To Upload:</b></td> <td><INPUT NAME="file" TYPE="file"></td> </tr> <tr> <td colspan="2" align="center"> </td> </tr> <tr> <td colspan="2" align="center"><input type="submit" value="Send File"> </td> </tr> <table> </center> </FORM> </BODY> </HTML>
2)UploadServlet.java:
import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import java.sql.*; public class UploadServlet extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); String saveFile=""; String contentType = request.getContentType(); if((contentType != null)&&(contentType.indexOf("multipart/form-data") >= 0)){ DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; while(totalBytesRead < formDataLength){ byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; File ff = new File(saveFile); FileOutputStream fileOut = new FileOutputStream(ff); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); out.println("You have successfully upload the file:"+saveFile); Connection connection = null; String connectionURL = "jdbc:mysql://localhost:3306/test"; ResultSet rs = null; PreparedStatement psmnt = null; FileInputStream fis; try{ Class.forName("com.mysql.jdbc.Driver").newInstance(); connection = DriverManager.getConnection(connectionURL, "root", "root"); File f = new File(saveFile); psmnt = connection.prepareStatement("insert into file(file_data) values(?)"); fis = new FileInputStream(f); psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length())); int s = psmnt.executeUpdate(); if(s>0){ System.out.println("Uploaded successfully !"); } else{ System.out.println("Error!"); } } catch(Exception e){e.printStackTrace();} } } }
3)servlet mapping in web.xml:
<servlet> <servlet-name>UploadServlet</servlet-name> <servlet-class>UploadServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>UploadServlet</servlet-name> <url-pattern>/UploadServlet</url-pattern> </servlet-mapping>
Ads