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| Problem with picture |
Expert:DARE
Hi,
I Develope a School Automated System that takes a details from the user interface and deposited into the database (MSSQL), i make the registrar to be able to upload the student picture from the System picture Folder and display it on the User Interface. Now, i want the registrar to submit the picture to the database (MSSQL), after submitting a refrence in a dialog notifying the registrar about the successful submition of the details and with the picture should show in a dialog box. and more so, i want the registrar to be able to upload this picture with the correspounding student details when He/She is trying to Update the details.
Please solve this proble with Microsoft Database (MSSQL)
Thanks Programmer.
Please help to solve this |
| Answers |
Hi Friend,
To upload and insert the image into database, try the following code:
1)page.jsp: <%@ page language="java" %> <Html> <HEAD><TITLE>Display file upload form to the user</TITLE></HEAD>
<BODY> <FORM ENCTYPE="multipart/form-data" ACTION="upload.jsp" METHOD=POST> <br><br><br> <center><table border="2" > <tr><center><td colspan="2"><p align="center"><B>UPLOAD THE FILE</B><center></td></tr> <tr><td><b>Choose the file To Upload:</b> </td> <td><INPUT NAME="file" TYPE="file"></td></tr> <tr><td colspan="2"> <p align="right"><INPUT TYPE="submit" VALUE="Send File" ></p></td></tr> <table> </center> </FORM> </BODY> </HTML>
2)upload.jsp: <%@ page import="java.io.*" %> <%@ page import="java.sql.*" %>
<% String contentType = request.getContentType(); if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\"")); out.println(saveFile); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream(saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close();
%><Br><table border="2"><tr><td><b>You have successfully upload the file by the name of:</b> <% out.println(saveFile);%></td></tr></table> <% Connection connection = null; String connectionURL = "jdbc:mysql://192.168.10.112:3306/file"; ResultSet rs = null; PreparedStatement psmnt = null; FileInputStream fis; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); connection = DriverManager.getConnection(connectionURL, "root", "root"); File f = new File(saveFile); psmnt = connection.prepareStatement("insert into file(file_data) values(?)"); fis = new FileInputStream(f); psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length())); int s = psmnt.executeUpdate(); if(s>0) { System.out.println("Uploaded successfully !"); } else { System.out.println("unsucessfull to upload file."); } } catch(Exception e){e.printStackTrace();} } %>
Thanks
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