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| Java programs |
Expert:Ruby
Could you please write the followong programs for me..
Thanks in advance
1)1. write a program that reads a string composed of 12 characters then splits it into 4 different strings each composed of three characters. Print the resulting strings each on a separate line; use printf.
2.)Write a program that reads a string s then another string p contained in s. Then form 3 strings extracted from s: the first part of s that does not contain p, the part that contains p and the last part. Print each of the three strings with its length and its position in s use printf. |
| Answers |
Hi friend,
Code to solve the problem :
Answer1 :
import java.io.*;
class StringExample
{
public static void main(String[] args) throws IOException
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter 12 character String");
String str= br.readLine();
if(str.length()==12)
{
for(int i=0;i<str.length();i++)
{
if(i%4==0)
System.out.println(str.substring(i,i+4));
}
}
else
{
System.out.println("You Enter 12 character String");
}
}
}
Answer2 :
import java.io.*;
class StringExample1
{
public static void main(String[] args) throws IOException
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter First String");
String str1= br.readLine();
System.out.println("Enter second String");
String str2= br.readLine();
int index = str1.indexOf(str2);
String firstPartString = str1.substring(0,index);
System.out.println("firstPartString " + firstPartString);
System.out.println("firstPartString length : " + firstPartString.length());
String secondPartString = str1.substring(index,index+str2.length());
System.out.println("secondPartString " + secondPartString);
System.out.println("secondPartString length : " + secondPartString.length());
String thirdPartString = str1.substring(index+str2.length());
System.out.println("thirdPartString " + thirdPartString);
System.out.println("thirdPartString length : " + thirdPartString.length());
}
}
Thanks
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