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| java help |
Expert:Maurice
Code a catch block that catches a NumberFormatException and then prints the name of the class that the exception was created from along with the message associated with the exception to the standard error output stream.
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| Answers |
Hi friend,
Code a catch block that catches a NumberFormatException :
class NumberFormatExceptionExample
{
public static void main(String[] args)
{
String[] ar={"Roseindia", "Hello World", "1234"};
String str="";
int num;
for(int count=0;count<ar.length;count++)
{
System.out.println("Input : " + ar[count]);
try
{
str=ar[count];
num=Integer.parseInt(str);
System.out.println("Numbers are "+num);
}
catch (NumberFormatException e)
{
System.out.print("Sorry, \""+str+"\" is not an integer.");
System.out.println(" Try again");
System.out.println("->"+e); // -> added to identify this line.
e.printStackTrace();
}
}
}
}
For more information on Exception Handling in Java visit to :
http://www.roseindia.net/java/exceptions/
Thanks
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Vineet
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