servlets

Expert:shaziya
hi deepak,
u had replied my question for employee details.. i compiled it and a class file file was created also without any error. but when i run it by giving the command java InsertDataAction.java it is giving a error as,
Exception in thread "main" java.lang.NoClassDefFoundError:InsertDataAction/java

can u plzz tel me whats the error .. the program which u had given is as follows:

package javacode;

import java.io.*;
import java.sql.*;

import javax.servlet.*;
import javax.servlet.http.*;

public class InsertDataAction extends HttpServlet{
public void doGet(HttpServletRequest request, HttpServletResponse response)throws
ServletException, IOException{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
System.out.println("Insert data Example!");
String driver = "com.mysql.jdbc.Driver";
String url = "jdbc:mysql://192.168.10.211:3306/";;
String db = "amar";
String userName = "amar";
String password = "amar123";
Connection con = null;
try{
Class.forName(driver);
con = DriverManager.getConnection(url+db,userName,password);
try{
Statement st = con.createStatement();
String firstname=request.getParameter("empname");
String midname=request.getParameter("midname");
String lastname=request.getParameter("lastname");
String contect=request.getParameter("address");
String dob=request.getParameter("dob");
String eml=request.getParameter("email");
String position=request.getParameter("position");
String comname=request.getParameter("comname");
String salary=request.getParameter("salary");
String teleno=request.getParameter("teleno");
String mobileno=request.getParameter("mobileno");
String state=request.getParameter("state");
String city=request.getParameter("city");
int val = st.executeUpdate("insert empdetail values('"+firstname+"','"+midname+"','"+lastname+"','"+contect+"','"+dob+"','"+eml+"','"+position+"','"+comname+"','"+salary+"','"+teleno+"','"+mobileno+"','"+state+"','"+city+"')");

con.close();
out.println("success");
}
catch (SQLException ex){
System.out.println("SQL statement is not executed!");
}
}
catch (Exception e){
e.printStackTrace();
}

}
}

Answers

Hi shaziya

i am sending servlets link , read more and more information about servlet. how to compile and how to run servlets program.This is running program but you are not able. This program not give you result on command prompt.

so read for more information at :

http://www.roseindia.net/servlets/

Thanks.

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